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0.25=0.4*x+0.25*x^2
We move all terms to the left:
0.25-(0.4*x+0.25*x^2)=0
We get rid of parentheses
-0.4*x-0.25*x^2+0.25=0
We add all the numbers together, and all the variables
-0.25x^2-0.4x+0.25=0
a = -0.25; b = -0.4; c = +0.25;
Δ = b2-4ac
Δ = -0.42-4·(-0.25)·0.25
Δ = 0.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.4)-\sqrt{0.41}}{2*-0.25}=\frac{0.4-\sqrt{0.41}}{-0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.4)+\sqrt{0.41}}{2*-0.25}=\frac{0.4+\sqrt{0.41}}{-0.5} $
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